ANSWER

10-11 year olds

From Bogotá until she left Méjico 7h 35mn. From Mexico to San José  2h 55mn. Total: Fom Bogotá (14:25) to San José (23:55) 10 hours and 30 minutes. Let’s explain:

- From Bogotá (14:25)  to  México (19:20) there are 4 hours and 55 minutes.

-In Mexico she spends 2 hours and 40 minutes until she gets on her next flight. The flight from Mexico to San José left at 19:20 + 2h 40mn  =  21:60 = 22h. Until then  (from Bogotá until the plane took off in Mexico)   4h 55mn have gone by so if we add +  2h 40mn.  =  6h 95mn = 7h 35mn.

- From Méjico (22:00)  to  San José (23:55) it seems 1h 55mn, but since in Costa Rica the clock always shows an hour less, at that time, in Mexico and Colombia is 24.55. Since the plane left Mexico at at 22:00 we know that it has been flying for 2h 55minutes.

- Adding all those times we can get the the amount of time she took on her trip. 4h 55mn  +  2h 40mn.  + 2h 55mn =  8h  150mn = 10h 30mn.

From Bogota to San Jose could have been solved in a different way: From Bogota (14:25)  to  San José (23:55) is 9h 30mn. But 1 hour mut be added due to the difference showed for he time in each country (Costa Rica shows 1 hour less than Colombia). 9h 30mn + 1h = 10h 30mn.